s0 =
ComputeDiffLimit(pupil,nm)
Compute the diffraction limit for coherent light.
(For incoherent light the answer is 2*s0.)
See page 120 in Goodman.
"pupil" diameter in mm
"nm" is wavelength in nm
"s0" is highest spatial frequency passed by the pupil in cycles/deg
Goodman, J. W. (1968) Introduction to Fourier Optics.
San Francisco:
McGraw-Hill. Page 120.
Goodman's formula involves di, which I think is the distance to the
image. Goodman's formula gives the limit in
cycles/unit length. The formula below gives
the answer in cycles/degree.
Psychtoolbox/PsychOptics/ComputeDiffLimit.m